A uniform tube of length 60 cm stands vertically with its lower end dipping into water. When the length above water successively taken at 14.8 cm and 48.0 cm, the tube responds to a vibrating tuning fork of frequency 512 Hz. Find the lowest fi-equency to which the tube will respond when it is open at both ends.

A uniform tube of length 60 cm stands vertically with its lower end di

1.	A uniform tube of length 60 cm stands vertically with its lower end dipping into water. When the length above water successively taken at 14.8 cm and 48.0 cm, the tube responds to a vibrating tuning fork of frequency 512 Hz. Find the lowest fi-equency to which the tube will respond when it is open at both ends.
Answer» Solution :From the given resonating LENGTHS we can USE `48 - 14.8 = ((lambda)/(2))` `lambda` = 66.4 cm. THUS for given situaton wavelength is `lambda` is `lambda` = 64.4 cm so speed of sound is `v = nlambda = 512 xx 0.664` = 339.97 m/s Fundamental frequency of tube is `n_(0) = (v)/(2l) = (399.97)/(2 xx 0.6)` = 283.30 Hz.

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