Saved Bookmarks
| 1. |
A uniformaly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0muC//m^(2) Find the charge on the sphere. (b) What is the total electric flux leaving the surface of the sphere? |
|
Answer» SOLUTION :Here diameter of SPHERE `D=2.4 m, `hence radius R=`(D)/(2) =1.2 m ` and surface CHARGES density`sigma =80.0 mu C //m^(2)=80 xx 10^(-6)C//m^(2) ` ` therefore`Total charges on the sphere `q = sigma . 4pi R^(2)=80 xx 10^(-6)xx 4 xx 3.14 xx (1.2)^(2)=1.45 xx 10^(-3)C ` Here diameter of sphere `D=2.4 m, `hence radius R=`(D)/(2) =1.2 m ` and surface charges density`sigma =80.0 mu C //m^(2)=80 xx 10^(-6)C//m^(2) ` Total electric flux LEAVING the surface of sphere ` phi_in =(q)/(in_0) =( 1.45xx10^(-3))/(8.85xx10^(-12))=1.6 xx 10^(8)N m^(2)C^(-1)` |
|