A uniformly charged hemisphere of radius b and charge density rho has a hemispherical cavity of radiusa(a=b/2) cut from its centre. If the potential at the centre of the cavity is (nrhob^(2))/(16epsilon_(0)) then n=?

A uniformly charged hemisphere of radius b and charge density rho has

1.	A uniformly charged hemisphere of radius b and charge density rho has a hemispherical cavity of radiusa(a=b/2) cut from its centre. If the potential at the centre of the cavity is (nrhob^(2))/(16epsilon_(0)) then n=?
Answer» Solution :`V=int_(a)^(B)(K(2PIX^(2)DX)rho)/X` `V=2pikrho[(b^(2)-a^(2))/2]=pirhok(b^(2)-a^(2))` `b=2a` `v=3pikrhob^(2)`

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A uniformly charged hemisphere of radius b and charge density rho has a hemispherical cavity of radiusa(a=b/2) cut from its centre. If the potential at the centre of the cavity is (nrhob^(2))/(16epsilon_(0)) then n=?

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