Saved Bookmarks
| 1. |
(a) Use the Bio-Savart law to determine the magnetic field due to conduction current outside the plates (refer to Fig) at points 6.5cm,12cm and 15cm from the wire. Do the answer match with those in Ex. ? Explain. (b) If the conduction wire has a radius of 1.0mm, what is the maximum value of magnetic field due to the conduction current? [When you compare the answer to Ex.(b) and 6(b), you will appreciate why it is not easy to notice magnetic field due to the displacement current]. (c) Suppose the thin wire in Fig. is replaced by rods each of radius 12cm (i.e. we now have two long cylinder rods separated by a small gap). Will magnetic field configurations for r gt R be identical for the regions between the plates and outside the plates? |
|
Answer» Solution :(a) USING Biot-Savart law, mangetic field induction at a point outside a straight current carrying wire is given by `B=(mu_0I_D)/(2pir)` Now, since `I=I_D`, this formula is the same as in for `r gt R`. THEREFORE , for `r=12cm` and `15 cm`, answers are the same as INFOR `r=6.5 cm (r lt R)`, the two formulae differ. Here `B=4.6xx10^-7T`, greater than B is (b) B is maximum at the surface of the wire, `B=(mu_0I)/(2pir)=(4pixx10^-7)/(2pixx10^-3)=3.0xx10^-6T` [Here, `r=1.0mm=10^-3m]` This is much greater than the maximum value of B INDUE to this reason, it is not easy to notice magnetic field due to displacement current. (c) YES, since`I=I_D`, magnetic field Configuration are identical for `r gt R`. |
|