1.

A varies directly with B when C is constant and inverselywith C when B is constant. A=6, when B= 2 and C = 3. What is the value of A, when B=3 and C= 18?

Answer»

`(1)/(2)`
`(5)/(2)`
`(3)/(2)`
`(7)/(2)`

Solution :`"Given", A alpha B"" (1) ("C is constant.")`
`A prop (1)/(C) "" (2) ("B is constant.")`
From Eqs (1) and (2), we get
`A = (KB)/(C)," where " K " is constant".`
`(AC)/(B) = K`
(i) A = 6, B = 2, and C = 3
`THEREFORE K = (6 xx 3)/(2) = 9`
(ii) A = ?, B = 3, and C = 18
`(A xx 18)/(3) = 9`
`RARR A = (3)/(2)`
Hence, the CORRECT option is (c).


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