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A varying current in a coil change from 10A to 0 in 0.5sec. If the average emf induced in the coil is 220V, the self inductance of the coil is : |
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Answer» Solution :The MUTUAL inductance of two long coaxial SOLENOIDS, `M_(12)=M_(21)=(mu_(0)N_(1)N_(2)A_(1))/(l)=(mu_(0)N_(1)N_(2)(pir_(1)^(2)))/(l)[becauser_(1)ltltr_(2)]` |
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