A vehicle is moving on a circular track whose surface is inclined towa – InterviewSolution

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1.	A vehicle is moving on a circular track whose surface is inclined towards the horizon at an angle of `10^(@)`. The maximum velocity with which it can move safety is 36 km/hr. Calculate the length of the circualr track. `[pi=3.142]`
Answer» Given : `v=36 km//hr` `=(36xx1000)/(60xx60)` `=10m//s, theta=10^(@)` Now, `tan theta=(v^(2))/(rg)` `tan 10^(@)=(10xx10)/(r xx 9.8) ` `0.1763=(100)/(9.8r)` `r=(100)/(9.8 xx 0.1763)` `=57.87m` `therefore` Length of circular track `= 2pi r ` `=2xx3.142xx57.87` `=363.657 m`

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