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A vehicle of mass 10kg is moving with a velocity of 5 m/sec. To stop it in The required force in opposite direction is

Answer» 500 N Explanation: A vehicle mass of 10kg is moving with a velocity of 5ms. To stop it in 1/10th SEC the required force in opposite direction is ​ INITIAL Velocity  = 5 m/s Final Velocity = 0 m/s Time = 1/10  sec Using V = U + at => 0 = 5 + a(1/10) => a = -50 m/s² Force Required in opposite direction = -ma = -10 *(-50) = 500 N required force in opposite direction is ​ = 500 N


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