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A vertical circular coil of radius 8 cm and 20 turns is rotated about its vertical diameter with angular velocity 50 rev/s in a uniform horizontal magnetic fieldof 3xx10^(-2)T. If the coil forms a closed loop of resistance, the average power loss due to joule's heating effect is (R=10Omega) |
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Answer» SOLUTION :emf induced in coil is `E=NBA_(omega). Sin (omegat)` `"Max emf "E_(0)=NBA_(omega)=NB(pir^(2))omega` `E_(0)=20xx3xx10^(-2)xxpixx64xx10^(-4)xx2pi(50)` `60xx10^(-2)xxpi^(2)xx64xx10^(-4)xx100=3.84V` `"Max current "i_(0)=(E_(0))/(R)=0.384A` `"Average power loss "=E_("RMS")xxi_("rms")XX COS Phi=(1)/(2)E_(0)xxi_(0)` `=(1)(1)/(2)(E_(0)^(2))/(R)=0.737W` |
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