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a vertical pole of length 6m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long . find the height of the tower. |
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Answer» The HEIGHT of the tower is 42 m.Step-by-step explanation:Height of pole=AB=6 m Length of SHADOW of pole =BC=4 m Length of shadow of tower=EF=28 m In △ABC and △DEF ∠B=∠E=90° both 90° as both are vertical to ground ∠C=∠F (same elevation in both the cases as both SHADOWS are cast at the same time) ∴ △ABC ≅ △DEF by AA SIMILARITY criterion We know that if two triangles are similar, ratio of their sides are in proportion So, DE = 6 7 = 42 cmHence the height of the tower is 42 m. |
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