1.

a vertical pole of length 6m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long . find the height of the tower.​

Answer»

The HEIGHT of the tower is 42 m.Step-by-step explanation:Height of pole=AB=6 m  Length of SHADOW of pole =BC=4 m  Length of shadow of tower=EF=28 m  In △ABC and △DEF  ∠B=∠E=90°  both 90°  as both are vertical to ground   ∠C=∠F  (same elevation in both the cases as both SHADOWS are cast at the same time) ∴ △ABC ≅ △DEF by AA SIMILARITY criterion We know that if two triangles are similar, ratio of their sides are in proportion  So, DE = 6 7 = 42 cmHence the height of the tower is 42 m.



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