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A very long straight conductor has a circular cross- section of radius R and carries a current density J. Inside the conductor there is a cylindrical hole of radius a whose axis is parallel to the axis of the conductor and a distance b from it. Let the z-axis be the axis of the conductor, and let the axis of the hole be at x = b. Find the magnetic field on the y = axis at y = 2R. |
| Answer» Solution :`B_(x)=mu_(0)JR((1)/(4)-(a^(2))/(4R^(2)+B^(2))),B_(y)=-(mu_(0)J)/(2)((a^(2)b)/(4R^(2)+b^(2)))` | |