1.

A vessel at 1000 K contains CO_(2) with a pressure of 0.5 atm. Some of the CO_(2) is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is :

Answer»

0.3 atm
0.18 atm
1.8 atm
3 atm

Solution :`{:(CO_(2)(g)+C(s),hArr,2CO(g)),(0.5,,0),(0.5-x,,2x):}`
Now, `0.5-x+2x=0.8`atm
x = 0.3 atm
`P_(CO)=2xx0.3=0.6`atm
`P_(CO_(2))=0.5-0.3=0.2` atm
`K=((p_(CO))^(2))/(p_(CO_(2)))=(0.6xx0.6)/(0.2)=1.8` atm


Discussion

No Comment Found

Related InterviewSolutions