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A vessel contains `110 g` of water. The heat capacity of the vessel is equal to `10 g` of water. The initial temperature of water in vessel is `10^(@)C`. If `220 g` of ho, water at `70^(@)C` is poured in the vessel, the final temperature neglecting radiation loss, will beA. `70^(@)C`B. `80^(@)C`C. `60^(@)C`D. `50^(@)C` |
Answer» Correct Answer - D Let final temperature of water be `theta` Heat taken = Heat given `110xx1(theta-10)+10(theta-10)` `=220 xx 1(70-theta)` `rArr theta = 48.8^(@)C = 50^(@)C`. |
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