1.

A vessel contains 4.4 g of CO_(2). It means that it contains

Answer»

0.1 MOL of `CO_(2)`
`6.02xx10^(22)` MOLECULES of `CO_(2)`
8.8 G atoms of oxygen
1120 ML of `CO_(2)` at S.T.P.

Solution :`4.4g CO_(2)=(4.4)/(44)mol=0.1mol`
`=0.1xx6.02xx10^(23)"molecules"`
`=6.02xx10^(22)"molecules."`


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