1.

A vessel contains O_(2)andH_(2) in 2 : 1 molar ratio at 10 atm pressure then calculate ratio of their rate of diffusion.

Answer»

1:4
1:8
1:2
1:6

Solution :Ratio of pressure of `O_(2)` and `H_(2)` = molar ratio = 2:1
`r_(O_2)/(rH_2)=(P_(O_(2)))/(P_(H_2))SQRT((M_(H_2))/(M_(O_(2))))`
`2/1 sqrt(2/32)`
`= 2/1 xx 1/4`
`r_(O_(2))/(r_(H_(2)))=1/2`
`r_(O_(2)):r_(H_(2))=1:2`


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