1.

A vessel of depth d is half filled with liquid of refractive index mu_1, and half filled with liquid of refractive index mu_2. Bottom will be at depth ..... when viewed from top and perpendicularly to surface.

Answer»

`2D(mu_2)/(mu_1)`
`2d mu_1mu_2`
`d/2[(1)/(mu_1)+(1)/(mu_2)]`
`2d[(1)/(mu_1)+(1)/(mu_2)]`

Solution :
`(h_i)/(h_0)=(1)/(mu_2)`
`therefore h_i=(h_0)/(mu_2)=(d)/(mu_2)`
and `(h._i)/(h._0)=(1)/(mu_1)`
`therefore h._i=(h_i^1)/(mu_1)=(d)/(mu_2)`
VIEWED DEPTH of bottom,
`h_i+h._i=d/mu_2+d/mu_1=d[1/mu_1+1/mu_2]`


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