1.

A vessel of volume V contains ideal gas having mass density rhoat temperature Tand pressure p. After a portion of the gas is let out, the pressure in the vessel is decreased by Delta p . The mass of the released gas is

Answer»

<P>`rho V Delta p// p`
`(Delta p)/(p)`
`rho/p`
`(rhoV)^2 Delta p // p`

Solution :Given,
INITIAL VALUE of volume, pressure and temperature of an ideal gas in vessel.
`V_1 = V, P_1 = P " and " T_1 = T`
and density of gas ` = rho`Then,`V_2 = V - Delta V`
` P_2 =P - Delta P`
` T_2 = T_1`
By an ideal gas EQUATION,
`(P_1V_1)/(T_1) = (P_2 V_2)/(t_2) `
` P_1/P_2 = V_1/V_2 "" [ because T_1 = T_2] `
`(P)/(P - Delta P) = (V - Delta V)/(V) = 1 - (Delta V)/(V)`
` (Delta V)/(V) = 1 - (P)/(P - Delta P)`
` =(P - Delta P - P)/( P - Delta P)`
` Delta V = (- Delta PV)/(P - Delta P) `
`therefore `Mass of released gas ` = rho Delta V = (rho Delta PV)/(P - Delta P) ~~ (rho Delta P V)/(P)`


Discussion

No Comment Found

Related InterviewSolutions