1.

a volecity of 20 m/s and it up to distance of 5cm find the acceleration of the bullet in the wall

Answer»

u = 20 m/sv = 0s = 5 cm = 0.05 m

from 3rd equation, v² - u² = 2as⇒ 0 - (20)² = 2 × 0.05 × a⇒ 0.1 a = - 400⇒ a = - 4000 m/s²

deceleration will be - 4000 m/s



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