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a volecity of 20 m/s and it up to distance of 5cm find the acceleration of the bullet in the wall |
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Answer» u = 20 m/sv = 0s = 5 cm = 0.05 m from 3rd equation, v² - u² = 2as⇒ 0 - (20)² = 2 × 0.05 × a⇒ 0.1 a = - 400⇒ a = - 4000 m/s² deceleration will be - 4000 m/s |
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