1.

A voltaic cell is set up at 25^(@)C with the helf cell, Al^(3+)(0.001M)and Ni^(2+)(0.50M) Write an equation for the reaction that occurs when the cell generates an electric current and determine the cell potential. (Given E_(Ni^(2+)//NI)^(@)=-0.25V,E_(Al^(3+)//Al)^(@)=-1.66V)

Answer»


Solution :`NI^(2+)+2e^(-)toNi,E_(Ni^(2+)//Ni)=0.25-(0.0591)/(2)"LOG"(1)/(0.50)=-0.259V`
`Al^(3)+3e^(-)toAl,E_(Al^(3+)//Al)=-1.66-(0.0591)/(3)"log"(1)/(10^(-3))=-1.719V`
For EMF to be +ve, oxidation should OCCUR on Al-electrode. Cell reaction: `2Al+3Ni^(2+)to2Al^(3+)+3Ni`
`E_(cell)=-0.259+1.719V=1.46V`


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