A voltmeter having resistance of 1800 Omega is employed to measure the potential difference across 200 Omega resistance which is connected to DC power supply of 50 V and internal resistance 20 Omega. What is the percentage change in potential difference across 200 Omega resistance as a result of connecting voltmeter across it ?

A voltmeter having resistance of 1800 Omega is employed to measure the

1.	A voltmeter having resistance of 1800 Omega is employed to measure the potential difference across 200 Omega resistance which is connected to DC power supply of 50 V and internal resistance 20 Omega. What is the percentage change in potential difference across 200 Omega resistance as a result of connecting voltmeter across it ?
Answer» 0.01 0.05 0.1 0.2 Solution :`V_(1)=E-lr=50-(50)/(220)xx20=50-45=45.5V` Now, `V_(2)=50-(50)/(200)xx20=45` % change in POTENTIAL DIFFERENCE `=((45.5-45))/(50)xx100=1%`

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