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A voltmeter reading upto 10 V has a resistance of`1000 Omega`. It can be converted into an ammeter reading up ot 10 A by connecting a shunt ofA. `1Omega`B. `0.1Omega`C. `2Omega`D. `0.2Omega`

Answer» Correct Answer - A
`I_g =(V)/(R_v)=(10)/(1000)=(1)/(100)A`
here `R_v=G`
`therefore` Required shunt,
`S=((I_g)/(I-I_g)).G=1 Omega`


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