A w. In the given figure, ∆ABC is an equilateraltriangle and ∆BD – InterviewSolution

1.	A w. In the given figure, ∆ABC is an equilateraltriangle and ∆BDC is an isosceles righttriangle, right-angled at D. Then angle ACD = ?(b) 90°(d) 105°(a) 60°(C) 120°
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