1.

A water fountain on the ground sprinkles water all around it . If the speed of water coming out of the fountain is ` v` , the total area around the fountain that gets wet is :A. `(piv^(2))/(g^(2))`B. `(piv^(2))/(g)`C. `(piv^(4))/(g^(2))`D. `(piv^(2))/(2g)`

Answer» Correct Answer - c
Range, `R=(u^(2))/(g)`
`therefore` Maximum area `=piR^(2)=R((v^(4))/(g^(2)))`


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