InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A wave equation which gives the displacement along the y-direction is given by `y = 10^(-4) sin(60t + 2x)` where `x and y` are in meters and `t` is time in secinds. This represents a waveA. (a) travelling with a velocity of `30m//s` in the nrgative x dierctionB. (b) of wavelength `pim`C. ( c ) of frequency `30//pi hertz`D. (d) of amplitude `10^(-4m` travelling along the negative x- direction |
|
Answer» Correct Answer - A::B::C::D (a,b,c,d) `y = 10^(-4)sin(60t - 2x)` Comparing the given equation with the standered wave equation travelling in negative x-direction `y = a sin (omegat + kx)` we get amplitude `a = 1-^(-4)m` Also, `omega = 60rad//s` :. `2pif = 60` rArr `f = (30)/(pi)Hz` Also, `k = 2` rArr `(2pi)/(lambda) = 2` rArr `lambda = pim` We know that `v = flambda = (30)/(pi) xx pi = 30m//s` |
|