InterviewSolution
Saved Bookmarks
| 1. |
A wave travelling along X-axis is given by `y=2(mm) sin (3t-6x+pi//4)` where x is in centimetres and t in second. Write the phases and, hence, the find the phase difference between them at t=0 for two points on X-axis, `x=x_(1)=pi//3` cm and `x=x_(2)=pi//2` cm. |
|
Answer» At `t=0` `y=sin(-6x+pi//4)` phase at `x_(1),phi=(-6xxpi/(3)+pi/(4))=(7)/(4)pi` and that at `x_(2) is (-6xxpi/(2)+pi/(4))=(11)/(4)pi` the phase difference is `|(7)/(4)pi-(11)/(4)pi|=pi`, the dusturbation at the two point are out of phase. |
|