1.

A wave travelling along X-axis is given by `y=2(mm) sin (3t-6x+pi//4)` where x is in centimetres and t in second. Write the phases and, hence, the find the phase difference between them at t=0 for two points on X-axis, `x=x_(1)=pi//3` cm and `x=x_(2)=pi//2` cm.

Answer» At `t=0`
`y=sin(-6x+pi//4)`
phase at `x_(1),phi=(-6xxpi/(3)+pi/(4))=(7)/(4)pi` and that at
`x_(2) is (-6xxpi/(2)+pi/(4))=(11)/(4)pi`
the phase difference is `|(7)/(4)pi-(11)/(4)pi|=pi`, the dusturbation at the two point are out of phase.


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