1.

A weak acid of dissociation constant 10^(-5) is being titrated with aqueous NaOH solution. The pH at the point of one-third neutralisation of the acid will be

Answer»

`5 + lgo2 - LOG 3`
`5- log 2`
`5-log 3`
`5-log 6`

Solution :Itformsabasicbuffer
So , `PH =pk_a+ log(["salt"])/(["acid"])`
onethirdneutralisation means `(["salt"])/(["acid"])= [(1)/(3) XX (3)/(2)]`
`pH =5+log[1/2] or pH= 5- log 2`


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