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A weak monobasic acid is 1% ionized in 0.1 M solution at 25^(@)C. The percentage of ionization in its 0.025 M solution is

Answer»

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Solution :`HA HARR H^(+) + A^(-)`
`K = C alpha^(2) = 0.1 xx ((1)/(100))^(2), K = 10^(-5)`
`K = C alpha^(2)` or `10^(-5) = 0.025 xx alpha^(2)`
`alpha = sqrt((10^(-5))/(0.025)) RARR alpha = 0.02`
% age of ionization =2 .


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