A weak monobasic acid [pKa = 5 " at " 25^(@)C] is been neutralized by using NaOH. Select correct statement for the neutralisation process at 25^(@)C. [log3 = 0.48].

A weak monobasic acid [pKa = 5 " at " 25^(@)C] is been neutralized by

1.	A weak monobasic acid [pKa = 5 " at " 25^(@)C] is been neutralized by using NaOH. Select correct statement for the neutralisation process at 25^(@)C. [log3 = 0.48].
Answer» PH of the solution at 50% neutralisation = pKa of the WEAK acid pH of the solution at 25% neutralisation `= (1)/(2) pKa` of the weak acid pH of the solution at 75% neutralisation `= (3)/(2)` pKaof the weak acid pH of the solution at 100% neutralisation `lt`pKa of the weak acid Solution :During neutralisation of a weak acid by a strong BASE we can get an acidic buffer solution if reaction is completed by9.09% to 90.0%. For an acidic buffer `pH= pKa + "log" (["salt"])/([W.A])` Now At 50% neutralisation , [salt]= [W.A], pH= pKa At 25% neutralisation, [salt] `=(1)/(3) [W.A]`, pH= pKa- log 3= 4.52 At 75% neutralisation, [salt] = 3 [W.A], pH= pKa + log 3= 5.48 At 100% neutralisation STAGE we will OBTAIN an aq. solution of salt of W.A/S.B then `pH gt 7.00`.