1.

A weight lifted a load of 50 kgf to a height of 2.5s. calculate(1) the work done and (11) the power developed by him.take g =10N kg_1​

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Answer:

I THINK the UNITS mentioned are wrong, soI assume it as m=10kg, h=2.5 , and g=10 m/s^2

Answer-1000 joules

Explanation:

m=10kg

h=2.5

g=10 m/s^2.

Work done=P.E

So, P.E=mgh

=10x2.5x10

=1000 joules

As the TIME has not been mentioned in the QUESTION I don't the power. If you tell me the time I can tell you the answer.



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