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A weight lifted a load of 50 kgf to a height of 2.5s. calculate(1) the work done and (11) the power developed by him.take g =10N kg_1 |
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Answer» Answer: I THINK the UNITS mentioned are wrong, soI assume it as m=10kg, h=2.5 , and g=10 m/s^2 Answer-1000 joules Explanation: m=10kg h=2.5 g=10 m/s^2. Work done=P.E So, P.E=mgh =10x2.5x10 =1000 joules As the TIME has not been mentioned in the QUESTION I don't the power. If you tell me the time I can tell you the answer. |
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