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A wheel having moment of interia `2 kgm^(-2)` about its axis, rotates at 50 rpm about this axis. The angular retardation that can stop the wheel in one minute isA. `(pi)/(36)"rad s"^(-2)`B. `(pi)/(18)"rad s"^(-2)`C. `(pi)/(72)"rad s"^(-2)`D. `(pi)/(9)"rad s"^(-2)` |
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Answer» Correct Answer - A The initial angular velocity `="50 rpm"=(5pi)/(3)"rad s"^(-1)` Using, `omega=omega_(0)+alphat` `alpha=(omega-omega_(0))/(t)=(0-(5pi)/(3))/(6)"rad s"^(-2)=-(pi)/(36)"rad s"^(-2)` |
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