InterviewSolution
Saved Bookmarks
| 1. |
A wheel is rotating at the rate of `33 "rev min"^(-1)`. If it comes to stop in 20 s. Then, the angular retardation will beA. `pi rad s^(-2)`B. `11 pi rads^(-2)`C. `(pi)/(200) rads^(-2)`D. `(11 pi)/(200) rads^(-2)` |
|
Answer» Correct Answer - D Angular retardation, `alpha=(omega_(0))/(t)" "(because 0=omega_(0)-alphat)` `=(2pixx33//60)/(20)=(11pi)/(200) "rad s"^(-2)`. |
|