A wheel is subjected to uniform angualr acceleration about its axis. Initially, its angualr velocity is zero. In the first `2 sec`, it rotates through an angle `theta_(1)`, in the next `2 sec`, it rotates through an angle `theta_(2)`. The ratio of `theta_(2)//theta_(1)` isA. `1`B. `2`C. `3`D. `5`

A wheel is subjected to uniform angualr acceleration about its axis. I

1.	A wheel is subjected to uniform angualr acceleration about its axis. Initially, its angualr velocity is zero. In the first `2 sec`, it rotates through an angle `theta_(1)`, in the next `2 sec`, it rotates through an angle `theta_(2)`. The ratio of `theta_(2)//theta_(1)` isA. `1`B. `2`C. `3`D. `5`
Answer» Correct Answer - C From `theta = omega_(1)t + (1)/(2) alpha t^(2)`, `theta_(1) = 0 + (1)/(2) alpha (2)^(2) = 2 alpha` `theta_(1) + theta_(2) = 0 + (1)/(2) alpha(4)^(2) = 8 alpha` `theta_(2) = 8 alpha - theta_(1) = 8 alpha - 2 alpha = 6 alpha` `(theta_(2))/(theta_(1)) = (6alpha)/(2alpha) = 3`

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A wheel is subjected to uniform angualr acceleration about its axis. Initially, its angualr velocity is zero. In the first `2 sec`, it rotates through an angle `theta_(1)`, in the next `2 sec`, it rotates through an angle `theta_(2)`. The ratio of `theta_(2)//theta_(1)` isA. `1`B. `2`C. `3`D. `5`

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