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A wheel with 10 metallic spokes each 0.5 m long rotated with a speed of 120 "rev"/"min" in a plane normal to the horizontal component of earth's magnetic field B_h at a place. If B_h = 0.4G at the place, what is the induced emf between the axle and the rim of the wheel ? (1 G = 10^(-4) T) |
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Answer» 0V `epsilon=(B omegaR^2)/2`…(i) (Here B=0.4 , `G=0.4 xx10^(-4)` T) `omega=120 "rev"/"MIN"=(240pi)/60"rad"/s` `omega=4pi` rad/s,R=0.5 m, N=10 `THEREFORE epsilon=(0.4xx10^(-4)xx4xx3.14xx(0.5)^2)/2` [ `because` From eqn. (i)] `=(0.4xx4xx3.14xx0.25xx10^(-4))/2` `=0.628xx10^(-4)` `=62.8xx10^(-6)` `=62.8 muV` |
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