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A wheel with 10 metallic spokes each 0.5m long is rotated with a speed of 120 rev/min in a plane normal to the horizontal component of earth's magnetic field H_(E) at a place. If H_(E)=0.4G at the place, what is the induced emf between the axle and the rim of the wheel? Note that 1G=10^(-4)T. |
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Answer» Solution :The emf induced, `epsilon=((1)/(2))omegaBR^(2)=((1)/(2))xx4pixx0.4xx10^(-4)xx(0.5)^(2)=6.28xx10^(-5)V` [Note that the NUMBER of SPOKES is immaterial because the EMFS across the spokes are in parallel.] |
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