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A whistle producting sound waves of frequencies 9500 Hz and above is approaching a stationary person with v ms^(-1). The velocity of sound in air is 300 ms^(-1) . If a person can hear frequencies upto 10,000 Hz, the maximum value of v upto which he can hear the whistle is : |
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Answer» `15 SQRT(2) ms^(-1) ` 10,000 = `((300)/(300 - U_(s)) ) . 9500` `rArr U_(s) = 15 ms^(-1)`. So correct CHOICE is (C). |
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