1.

A white solid A reacts with dilute H_(2)SO_(4) to produce a colourless gas B and a colourless solution C. the reaction between B and acidified dichromate yields a green solution and a slightly coloured precipitate D. the substance D, when burnt in air, gives a gas E which reactswith B to yield D and a colourlesss liquid. anhydrous copper sulphate turns blue with this colourless liquid. the addition of aqueous NH_(3) or NaOH toC produces a precipitate that dissolves in an excess of the reagent to form a clear solution. Q. What would happen if the gas E were passed through an acidified KMnO_(4) solution?

Answer»

Bleaching of the permangnate solution without any precipitation
Bleaching of the perrmangnate solution which would show a yellowish white turbidity
Bleaching of the permangnate solution and the formation of a brown precipitate
No ACTION

Solution :One of the three COLOURLESS gases `-CO_(2),SO_(2) and H_(2)S`- is generally produced by the action of dilute `H_(2)SO_(4)` on a salt. As the gas turns acidified dichromate solution green along with the formation of slightly COLOURED precipitate (may be S), the gas seems to be `H_(2)S` and so the SUBSTANCE A seems to be a sulphide. again, the action of `NH_(3)` or an NaOH solution on the solution of the substance in dilute
`H_(2)SO_(4)` suggets that the substance is a zinc salt. thus, A is most likely ZnS. let us go through the reactions now.


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