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A wiere mesth consisting of very small squares is viewed at a distances of 8cm through a magnifying lens of fcoal length 10cm, kept close to the eye. The magnification produced by the lens is |
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Answer» 5 Given `f=10cm` (as lens is converging) `u=-8cm` (as object is placed on LEFT SIDE on thelens) Substituting these values in Eq. (i) We get `1/10=1/v-1/(-8)implies1/v=1/10-1/8implies1/v=(8-10)/80` `:. V=80/(-2)=-40CM` Hence, MAGNIFICATION produced by the lens `m=v/u=(-40)/(-8)=5` |
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