A wire forming a rectangle of dimensions 9 cm and 6.4 cm, is stretched

1.	A wire forming a rectangle of dimensions 9 cm and 6.4 cm, is stretched and bent again to form a circle. What would the diameter of the circle be?
Answer» ANSWER: Perimeter of rectangle = 2(l+b) = 2( 9+6.4) = 2 X 15.4 = 30.8 CM then perimeter or circumference of CIRCLE is also 30.8cm Circumference = 2πr 30.8 = 2 x 22/7 x r 30.8 = 44/7 x r 30.8 x 7/44 = r 4.9cm = r Diameter = 2r = 2 x 4.9 = 9.8 cm

A wire forming a rectangle of dimensions 9 cm and 6.4 cm, is stretched and bent again to form a circle. What would the diameter of the circle be?

Answer»

Perimeter of rectangle = 2(l+b)

= 2( 9+6.4)

= 2 X 15.4

= 30.8 CM

then perimeter or circumference of CIRCLE is also 30.8cm

Circumference = 2πr

30.8 = 2 x 22/7 x r

30.8 = 44/7 x r

30.8 x 7/44 = r

4.9cm = r

Diameter = 2r

= 2 x 4.9

= 9.8 cm