InterviewSolution
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InterviewSolution
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A wire has a mass `0.4 +- 0.004g` and length `8 +- 0.08(cm)` The maximum percentage error in the measurement of it density is `4%` The radius of the wire is `r +- Delta r` find `Delta r`A. `0.02r`B. `0.01 r`C. `0.03r`D. `0.1r` |
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Answer» Correct Answer - b `rho= (m)/(pi r^(2)L)` `(Delta rho)/(rho) xx 100[((Delta m)/(m)+ 2 (Delta r)/(r ) + Delta L)/(L)]xx 100` `= (0.01 + 2(Delta r )/(r ) + 0.01) xx 100 = 4`(given) `or `100(Delta r)/(r ) = 1` `Delta r = 0.01r` |
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