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A wire has a resistance of 2.5Omega at 100^(@)C. Temperature coefficient of resistance of the material alpha=3.6xx10^(-3)K^(-1). Find its resistance at 0^(@)C. |
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Answer» SOLUTION :`alpha=(R_(t)-R_(0))/(R_(0)(t_(2)-t_(1))),3.6xx10^(-3)=(2.5xxR_(0))/(R_(0)xx100)` `R_(0)=(2.5)/(1.36),R_(0)=1.83Omega` |
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