A wire is (7x – 3) metres long. A length of (3x – 4) metres is cut for use (a) How much wire is left? (b) If this left out wire is used for making an square. What is the length of each side of the square so formed?

A wire is (7x – 3) metres long. A length of (3x – 4) metres is cut

1.	A wire is (7x – 3) metres long. A length of (3x – 4) metres is cut for use (a) How much wire is left? (b) If this left out wire is used for making an square. What is the length of each side of the square so formed?
Answer» -step explanation:Given LENGTH of the wire = ( 7x - 3 ) mLength of Wire used = ( 3x - 4 ) m< B > Wire left – < /b >Wireleft–= Original length of wire - Length of wire used= ( 7x - 3 ) - ( 3x - 4 )= 7x - 3 - 3x + 4= 4x - 7Hence, < b > < U > ( 4x - 7 ) m of wire is left. < /b > < /u >(4x−7)mofwireisleft.Now, Length of wire which is left is used to make an equilateral triangle.So, the wire length will be equal to < b > perimeter < /b >perimeter of the triangle.As we know that the length of side of equilateral triangle is same.Let, each side of equilateral triangle = 'a' cm< u > Perimeter of equilateral triangle = 3 ( a ) < /u >Perimeterofequilateraltriangle=3(a)•°•4x - 7 = 3 ( a )a = ( 4x - 7 ) / 3Hence, < b > < u > Side of equilateral triangle is ( 4x - 7 ) / 3 m. < /b > < /u >Sideofequilateraltriangleis(4x−7)/3m.