1.

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of eachside? Also find which shape encloses more area and by how much?​

Answer»

⭐ Question

A wire is in the shape of a RECTANGLE. Its LENGTH is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a SQUARE, what will be the measure of each SIDE. Also find which shape ENCLOSES more area?

{\underline{\bf { Given \: that } }}

  • A wire is in the shape of a rectangle has length of 40 cm and breadth of 22 cm.

{\underline{\bf { To \: find: } }}

  • If the same wire is rebent in the shape of a
  • square, what will be the measure of each side.

  • Also find which shape encloses more area and by how much?

{\underline {\bf { Solution : } }}

According to question-

\rm\blue {Perimeter \: of \: rectangle = Perimeter \: of \: square }

\rm { \therefore 2(Length + Breadth) = 4 \times Side }

\rm { \longrightarrow 2 (40 + 22) = 4 \times Side }

\rm { \longrightarrow 2 \times 62 = 4 \times Side }

\rm { \longrightarrow 124 = 4 \times Side }

\rm { \longrightarrow  Side = \dfrac{124}{4}}

\rm\red { Side  = 31 cm}

Now,

\rm {\implies Ar. \: of \:rectangle = length \times breadth }

\rm {\implies Ar. \: of \:rectangle = 40 \times 22 = 880 {cm}^{2} }

and,

\rm { \implies Area \: of \: square = {(Side)}^{2} }

\rm {  \implies 31 \times 31 = 961 {cm}^{2} }

\rm\purple { 880 {cm}^{2} < 961 {cm}^{2} }

Therefore, the square-shaped wire encloses more area.



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