1.

A wire is stretched by2xx10^(-2)m due to the force of 10 N. Then the amount of work done to stretchthe wire to a displacement of 4xx10^(-2)m is

Answer»

0.04 J
0.4 J
40 J
400 J

Solution :`W_(1) =(1)/(2) Fl=(1)/(2)xx10 xx 2 xx 10^(-2) =0.1J`
`(W_(2))/(W_(1))=((l_(2))/(l_(1)))^(2)=((4xx10^(-2))/(2XX10^(-2)))^(2)=4`
`W_(2)=4W_(1)`
`=4xx0.1=0.4J`.


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