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A wire is stretched so as to change its diameter by 0.25% . The percentage change in resistance is |
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Answer» `4.0%` So, V = Al or L = V/A Now, `R=(rho l)/(A)=(rho V)/(A^(2))=(rho V)/(pi^(2)D^(4)//16)=(16rho V)/(pi^(2)D^(4))` Taking logarithm of both the side and differentiating it, we get `(DELTA R)/(R )=-4 (Delta D)/(D)` or `(Delta R)/(R )=-4xx(-0.25)=1.0%` |
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