1.

A wire is stretched such that its volume remains constant. The Poisson's ratio of the material of the wire is

Answer»

`0.25`
`0.50`
`-0.25`
`-0.50`

Solution :`SIGMA=((DELTA R)/( r))/( (Delta L)/( I))`
volumeremainconstant`V= Alimplies+-(Delta V )/(V )= +-(Delta A)/( A )+-(Delta l )/(I)implies 0= ( 2Deltar)/( r )+(Delta l )/(I)`
`((Deltar)/(r ))/(( Deltal)/(I)) = -1/2=- 0.5`


Discussion

No Comment Found

Related InterviewSolutions