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A wire length 2.5km and resistance 35 ohm has fallen from a height of 10m in earth's horizontal field of 2xx10^-5T. What is the current through the wire? |
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Answer» SOLUTION :`V^2` = 2gh` ` THEREFORE v = sqrt2gh = 14m/s.` `E = B_Hlv = 2xx10^-5xx2.5xx10^3xx14` ` = 70xx10^-2 ` ` therefore i = e/R = 2xx10^-2 = 0.02A`. |
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