A wire of `9.8xx10^(-3) kg/m` passes over a frictionless light pulley fixed on the top of a frictionless inclined plane which makes an angle of `30^(@)` with the horizontal. Masses m and M are tied at the two ends of wire such that m rests on the plane and M hangs freely vertically downwards. the entire system is in equilibrium and a transverse wave propagates along the wire with a velocities of `100 m//s`.A. `m=20 kg`B. `M=5 kg`C. `(m)/(M)=(1)/(2)`D. `(m)/(M)=2`

A wire of `9.8xx10^(-3) kg/m` passes over a frictionless light pulley

1.	A wire of `9.8xx10^(-3) kg/m` passes over a frictionless light pulley fixed on the top of a frictionless inclined plane which makes an angle of `30^(@)` with the horizontal. Masses m and M are tied at the two ends of wire such that m rests on the plane and M hangs freely vertically downwards. the entire system is in equilibrium and a transverse wave propagates along the wire with a velocities of `100 m//s`.A. `m=20 kg`B. `M=5 kg`C. `(m)/(M)=(1)/(2)`D. `(m)/(M)=2`
Answer» Correct Answer - a., d. `v=sqrt((T)/(mu))` For equilibrium `Mg=mg sin 30=T` `M=m//2` `100=sqrt((Mg)/(9.8xx10^(-3)))=sqrt((M(9.8))/(9.8xx10^(-3))` `100=sqrt(M(1000))` `M=10 kg and m=20 kg`

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