1.

A wire of cross-section A is stretched horizontally between two clamps located 21 metre apart. A weight W kg is suspended from the mid point of the wire. If the mid point sags vertically through a distance x < l the strain produced is :

Answer»

`(2x^(2))/(l^(2))`
`(x^(2))/(l^(2))`
`(x^(2))/(2l^(2))`
NONE of these.

Solution :Here change in length is
`DELTAL=[AC+BC]-2l`
`=2(l^(2)+x^(2))^(1//2)-2l`

`=2l(1+(x^(2))/(l^(2)))^(1//2)-2l`
`=2l[1+1/2(x^(2))/(l^(2))]-2l=(x^(2))/l`
`therefore` STRAIN`=(Deltal)/(2l)=(x^(2))/(2l^(2))`.
Correct choice is (c).


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