1.

A wire of mass 100 g is carrying a current of 2A towards increasing x in the form of y=x^2(-2mlexle+2m). This wire is plasced in a magnetic field B=-0.02hatk tesla. The ascceleration of the wire ("in"m/s^2) is

Answer»

`-1.6hatj`
`-3.2hatj`
`1.6hatj`
zero

Solution :in UNIFORM field,

MEGNETIC foerce on POQ=magnetic force on straight wire PQ having the CURRENT. Hence,
`F=i(IxxB)i(PQxxB)`
`=2[(4i)XX(-0.02hatk)]`
`=(0.16hatj)`
`:. A=F/m=((0.16hatj))/0.1=(1.6hatj)m/s^2`


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