1.

A wire of uniform cross-section is stretched between two points 1m apart. The wire is fixed at oneend and n weight of 9 kg hung over a pulley at the other end produces fundamental frequency of 750Hz. If now thesuspended weight is submerged inn liquid of density (5/9) that of the weight, what will be the velocity and frequency of the waves propagating along the wire?

Answer»

Solution :Now as in case OFA WIRE under TENSION `v = sqrt(T/m)`
so `V_A/V_B = sqrt(T_A/T_B),i.e., V_B = 1500 sqrt(T_B/T_A) (or)`
`V_B = 1500 sqrt((MG.)/(Mg)) =1500 sqrt((g[1-sigma//rho])/g)[as g. =g(1 -sigma/rho)]`
or `V_B = 1500 sqrt(1 - 5/9) = 1000 m//s`
so from `v = f lambda , f_B = V_B/lambda_B = 1000/2= 500Hz` i.e.,in thissituation, `lambda =2m, f =500 Hz and v = 1000 m/s.


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